Topic #2: refrigerant gas is superheated when it enters condenser shell side. the superheated refrigerant gas is cooled first to saturated gas and then eventually to saturated liquid refrigerant when it leaves the condenser (shell side). thus, when the condenser tubes are clean, i. e., mineral fouling free, the temperature of the liquid refrigerant leaving condenser is almost equal to the water temperature leaving condenser. the difference between the two temperatures is called “condenser approach.” in other words, when a condenser is perfectly managed, the condenser approach is zero or one-two deg c. with severe mineral fouling inside condenser tube, the condenser approach temperature can be over 10 degc. explain why the condenser approach temperature increases over 10 degc using mathematical equations from heat transfer and thermodynamic theories

russian is not my first language, so i'm afraid i can't write out an answer in russian, but hopefully you can find a way to do so. here's my best translation of the problem: you're given a plot of a particle's position in one-dimensional space over time, and you're asked to find either the total distance traveled by the particle after 6 seconds had elapsed, or the total displacement of the particle after 6 seconds.

if you want the total distance traveled, you would first need to determine the particle's velocity as a function of time, then integrate that over the 6-second interval. we know the position function is quadratic with roots at 0 and 6, so we have

where is unknown. because the position is parabolic, there is symmetry about the midpoint at , and we know that

so that the position function is

which means the velocity is

then the total distance traveled is

so the total distance traveled is 20 m.

on the other hand, if you want to find displacement: the particle starts at and ends at , so its displacement is 0.

i really dont know but i will try okay.

so i think u would just add all them up and get your answer..