How many joules of heat are absorbed to raise the temperature of 435 grams of water at 1 atm from 25°c to its boiling point?

Explanation:

The amount of heat absorbed in the temperature variation of a material is:

  (1)

Where:

 is the mass  of water

 is the specific heat of the element. In the case of water

 is the variation in temperature, which in this case is    

(The boiling point of water at the pressure of 1 atm is  )

Rewriting equation (1) with the known values:

(2)

  (3)

Nevertheless, we are asked to find this value in Joules. So, we have to convert this 32625 calories to Joules, knowing the following:

  (4)

Hence:

if they have a finite resultant

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