Aboy pushes a toy car with the force of 50n. the force of friction as the car moves is 5n. what is the net force on the car

Explanation:

The first Newton Law of Motion states that an object at rest or describing a uniform straight line motion (moving at constant velocity), will remain at rest or moving unless a force is applied to it and changes its state of rest or motion.

According to his law, an object in rest can be in equilibrium (net force equals to zero), and a moving object can also be in equilibrium, as long as it keeps a constant velocity.

So, in the case of the toy car the forces acting on it (considering there is equilibrium between the normal force and the weight of the toy) are:

F1=50 N in the direction of the movement of the car

F2=-5 N (in the opposite direction of the movement of the car, that s why it has the negative sign)

Therefore the net force F is:

F=F1+F2=50N - 5 N

F=45N

well clustered together.

points close on a scatter diagram

in order to follow the instructions and complete the statements, i need to use data from table c of your student guide. can you think of a way to let me see your student guide for a while ? i can't answer the question without the data in table c.