Alight bulb with resistance of 22 ohms is connected to a 110 v battery. what is the current flowing through the circuit?

5A. The current that flowing through the circuit with a lightbulb of 22Ω connected to a voltage source of 110V is 5A.

The key to solve this problem is using Ohm's Law equations V = I*R, where V is the voltage drop, I is the current that flow through the element and R its resistance.

Clear I from the equation above:

I = V/R

With V = 110V, and R(lightbulb) = 22Ω

I = 110V/22Ω = 5A

a

explanation:

because they are cartillidge

r = ρ x length / area  

ρ = r x area / length  

ρ is in ohm-meters  

in basic units, it is m³kg/s³a²  

i think this is it.