Ahot air balloon is rising upward with a constant speed of 2.50m/s. when the balloon is 3.0 m above the ground, the balloonist drops a compass over the side of the balloon. how much time elapses before the compass hits the ground?
ps. do you mind explaining why you chose a certain formula or why you plugged in certain values?

Let's assume that the balloonist dropped the compass over the the side as the balloon still rising upward at 2.5m/s

So you have:
Vi = -2.5 m/s (because the compass is still going with the balloon as it starts to fall down)
d = 3 m
a = 9.81 m/s^2

At first you use this formula to find the Vf (finally velocity):
Vf^2 = Vi^2 + 2ad
Vf^2 = 6.25 + 2(9.81)(3)
Vf^2 = 65.11
Vf = 8.07 m/s

Finally you use this formula to find the time:
Vf = Vi +at
8.07 = -2.5 + (9.81)t
10.57 = (9.81)t
t = 1.08 s

Your final answer is 1.07 seconds.

The correct answer is  ait's a process by which rocks and minerals undergo in their composition^o^