Anew ride being built at an amusement park includes a vertical drop of 71.6 meters. starting from rest, the ride vertically drops that distance before the track curves forward. if the velocity at the bottom of the drop is 10.0 m/s and the mass of the cart and passengers is 3.5 x 104 kg, how much potential energy was converted into thermal energy (heat)? a. 2.3 x 10^7 j b. 2.6 x 10^7 j c. 4.3 x 10^7 j d. 6.7 x 10^7 j

B. 2.6 × 10⁷ J

Explanation:

First let's find the gravitation potential energy due to the height

P.E= m×g×hwhere m is the mass of cart and passengers, g acceleration due to gravity and h is the height of the vertical ride

P.E= 3.5×10⁴ × 9.8 × 71.6 = 24558800 J

Finding the kinetic  due to the final velocity

K.E = 1/2 mv²where v is velocity that represent how fast the cart was moving before reaching the bottom of the drop

K.E = 1/2 × 3.5×10⁴× 10² = 1750000 J

⇒When the cart starts to ride from rest, the potential energy is converted into kinetic energy which is then converted to thermal energy

Total energy that was converted to heat = 24558800+1750000 = 26308800

=2.6 × 10⁷ J

you have to draw the persons position over there