Hello, me understand this question

Fnet = 1.125x10⁻²²N.

To solve this problem we are going to use Coulomb's Law equation as follow:

Where:

K is  a constant of proportionality.

q₁ and q₂ are charges that could be positive or negative.

r is the distance between charges.

To calculate the net electrostatic force on q₂ due the other two charges, we have to calculate the force exerted by q₁ on q₂, and the force exerted by q₃ on q₂. Then, the net electrostatic force on q₂ due the other charges is Fnet = F₁₂ + F₃₂.

First, the charges are located on the + X axis of a coordinate system.

The force exerted by q₁ on q₂

Both charges are positive and exist repulsion between them. Then, q₂ experiences a repulsion force due q₁ towards the side + X which means F₁₂ is positive

The force exerted by q₃ on q₂.

The charges has different signs and exist atraction between them. Then, q₂ experiences an atraction force due q₃ towards the side + X which means F₃₂ is positive.

The net electrostatic force on q₂ due the other charges is:

Fnet = 4.50x10⁻²³N + 6.75x10⁻²³N = 1.125x10⁻²²N

hello, i am papaguy.

i have found an answer to your question but use it as information.

information: because weak acids/bases have low concentration of hydrogen ions, the addition of water has a large impact on the ph. 2. a difference in 1 unit is a 10x difference in concentration for example; a liquid with ph of 3 is 10x more acidic than a liquid with a ph of 4. therefore, a liquid with a ph of 3 is stronger.

best of luck!