The momentum of light is exactly reversed when reflected straight back from a mirror, assuming negligible recoil of the mirror. thus the change in momentum is twice the photon momentum. suppose light of intensity 1.00 ~\text{kw/m}^21.00 kw/m 2 reflects from a mirror of area 2.00 ~\text{m}^22.00 m 2 . using the most general form of newton’s second law, what is the force on the mirror?

the minimum constant speed at which she can catch the train is 2.7 m/s

given:

acceleration = 0.6

time = 4.5 s

to find:

velocity = ?

formula used:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

solution:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

v = 0 + (0.6 × 4.5)

v = 2.7 m/s

the minimum constant speed at which she can catch the train is 2.7 m/s

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