** (will give + brainliest answer) a skateboarder is starting at the top of a 50.0 meter hill. at the bottom of the hill the skateboarder is going 25 m/s. if the mass of the skateboarder is 52 kg, how much energy was lost in the downhill ride? a) 650 joules b) 9230 joules c) 16,250 joules

B

Explanation:

Energy at the top of the hill = energy at the bottom of the hill + energy lost

PE = KE + E

mgh = 1/2 mv² + E

(52 kg) (9.8 m/s²) (50.0 m) = 1/2 (52 kg) (25 m/s)² + E

25480 J = 16250 J + E

E = 9230 J

think about the oscillation of the toy shown in the video. when the toy is at the highest point of its motion, its velocity is zero and its acceleration is negative.

newton's first law of motion