Arunner is moving at a constant speed of 8.00 m/s around a circular track. if the distance from the runner to the center of the track is 28.2 m, what is the centripetal acceleration of the runner? 1.13 m/s2 0.284 m/s2 3.53 m/s2 2.27 m/s2

Last option

2.27 m/s2

Explanation:

As the runner is running at a constant speed then the only acceleration present in the movement is the centripetal acceleration.

If we call a_c to the centripetal acceleration then, by definition

in this case we know the speed of the runner

The radius "r" will be the distance from the runner to the center of the track

The answer is the last option

t = 1/400 h   ⇔ 0.0025 h ⇔ 9s ⇔ 0.15 m

any of the answers are correct.

b

explanation: