Amissile is fired from a jet flying horizontally at mach 2 (2200 ft/s). the missile has a horizontal acceleration of 1000 ft/s2. calculate its horizontal velocity at 10.0 seconds after it is fired. (assume constant acceleration of the missile throughout its flight.) 12,200 ft/s 10,000 ft/s 2300 ft/s 7800 ft/s

12200 ft/s

Explanation:

The question is on constant acceleration

→Uniform acceleration motion is given by⇒⇒⇒     Vf=Vo+ at(a)

→Where Vf= final velocity=?

            Vo=initial velocity =2200 ft/s

              a= acceleration= 1000ft/s²

               t= 10.0 sec

Substitute values in (a) above

Vf=Vo+ at

Vf= 2200 + ( 1000×10) = 12200 ft/s

answer: at 24 february, 2014 the population gets twice of its initial population.

explanation:

since we have given that

the population for alpha city, t years after january 1, 2004 is given as

first we find out the initial population, i.e. t=0,

so, our quadratic equation becomes,

according to question, we have said that if the population has twice its initial population, then it becomes

so, time taken to reach this above mentioned population is given by

now, we know that time can't be negative so, we take t=9.149 years.

hence, at 24 february, 2014 the population gets twice of its initial population.