Astone is projected from the ground with a velocity 14m/s one second later it clears a wall 2 m high. the angle of projection is?

30°

Explanation:

y = y₀ + v₀ᵧ t + ½ gt²

Given: y₀ = 0 m, v₀ = 14 m/s, and g = -9.8 m/s².

At t = 1 s, y = 2 m.

2 = 0 + (14 sin θ) (1) + ½ (-9.8) (1)²

sin θ = 6.9/14

θ ≈ 29.5°

Rounded to one sig-fig, the angle of projection is about 30° from the horizontal.

it should be -8.6 cm hope this out

good for her? ? where is the question?