If a 20 kg artillery shell is launched vertically with a velocity of 37 m/s, how high in meters does it rise? use the acceleration due to gravity as 9.8 m/s2.
or-
how do you calculate projectile motion? what are the formulas?

1. 69.8 m

The vertical motion of the shell is a uniformly accelerated motion, with constant acceleration towards the ground (acceleration due to gravity).

At the point of maximum height, the velocity of the projectile is zero:

v = 0

So we can find the maximum height by using the equation:

where

u = 37 m/s is the initial velocity

d is the maximum heigth

Solving for d,

2)

A projectile motion consists of two separate motions:

- A uniform motion along the x-direction, with constant velocity given by

where is the initial velocity, and the angle of launch

- A unformly accelerated motion along the y-direction, with initial velocity

and constant acceleration

(acceleration due to gravity) towards the ground.

The horizontal position of the projectile at time t is given by

while the vertical position is given by

where is the initial height of the projectile.

when the velocity of a mass on a spring is zero, the acceleration is at a maximum .

the minimum amperage that the current in this wire would have to have so that its weight is completely supported by the magnetic force due to earth's field, assuming that no other forces except gravity act on it