The spaceship intergalactica lands on the surface of the uninhabited pink planet, which orbits a rather average star in the distant garbanzo galaxy. a scouting party sets out to explore. the party\'s leader–a physicist, naturally–immediately makes a determination of the acceleration due to gravity on the pink planet\'s surface by means of a simple pendulum of length 1.26 m. she sets the pendulum swinging, and her collaborators carefully count 105 complete cycles of oscillation during 202 s. what is the result?

Explanation:

The period of a pendulum is given by:

(1)

where

T is the period

L is the length of the pendulum

g is the acceleration due to gravity

In this problem, we have:

L = 1.26 m is the length of the pendulum

The pendulum does 105 complete cycles in t=202 s, so the frequency is

and so the period is

Now that we know the period T and the length L, we can re-arrange the eq.(1) to find the acceleration due to gravity on the planet's surface:

probably not the "magnets"in the magnet, so to speak, are thought to be electrons orbiting in shells. vurrent loops two sides to the loop