Continuous and aligned fiber-reinforced composite with cross-sectional area of 340 mm2 (0.53 in.2) is subjected to a longitudinal load of 46500 n (10400 lbf). assume vf = 0.3, vm = 0.7, ef = 131 gpa and em = 2.4 gpa. (a) calculate the fiber-matrix load ratio. (b) calculate the actual load carried by fiber phase. (c) calculate the actual load carried by matrix phase. (d) compute the magnitude of the stress on the fiber phase. (e) compute the magnitude of the stress on the matrix phase. (f) what strain is expected by the composite?

(a) 23.4

The fiber-to-matrix load ratio is given by

where

is the fiber elasticity module

is the matrix elasticity module

is the fraction of volume of the fiber

is the fraction of volume of the matrix

Substituting,

(1)

(b) 44,594 N

The longitudinal load is

F = 46500 N

And it is sum of the loads carried by the fiber phase and the matrix phase:

(2)

We can rewrite (1) as

And inserting this into (2):

Solving the equation, we find the actual load carried by the fiber phase:

(c) 1,906 N

Since we know that the longitudinal load is the sum of the loads carried by the fiber phase and the matrix phase:

(2)

Using

F = 46500 N

We can immediately find the actual load carried by the matrix phase:

(d) 437 MPa

The cross-sectional area of the fiber phase is

where

is the total cross-sectional area

Substituting , we have

And the magnitude of the stress on the fiber phase is

(e) 8.0 MPa

The cross-sectional area of the matrix phase is

where

is the total cross-sectional area

Substituting , we have

And the magnitude of the stress on the matrix phase is

(f)

The longitudinal modulus of elasticity is

While the total stress experienced by the composite is

So, the strain experienced by the composite is

i just did an experiment like this in my science class. also the answer is yes, it will get separated because they are two opposites meaning if they are opposite they can not attract.

hope this .!