What is the value of work when a piston of volume 0.2 l expands against an external pressure of 200 kpa to a volume of 3.4 l?

This question involves the concepts of work done by the piston and the pressure-volume-work equation.

The value of work done will be "640 J".

The pressure-volume-work equation is given as follows:

where,

W = Work done by the piston = ?

P = External pressure = 200 KPa = 200000 Pa

ΔV = Change in volume = 3.4 L - 0.2 L = 3.2 L = 0.0032 m³

Therefore,

W = 640 J

Learn more about work done by piston here:

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The attached picture shows pressure-volume-work equation.

Explanation:

To calculate the work, given a change in volume we use the following formula:

Where is work, is pressure, is the final volume, and is the initial volume.

In this case:

We need to convert liters to (to get joule units in the work ) Since

Thus, thw work is:

the value of work in the expansion is

a solenoid is created by wrapping a l = 90 m long wire around a hollow tube of diameter d = 4.5 cm.   the wire diameter is d = 0.9 mm.   the solenoid wire is then connected to a power supply so that a current of i = 9 a flows through the wire.

randomized variablesl = 90 m

d = 4.5 cm

d = 0.9 mm

i = 9 a                                          

write an expression for the number of turns, n, in the solenoid. you do not need to take into account the diameter of the wire in this calculation.

calculate the number of turns, n, in the solenoid.

write an expression for the length of the solenoid (l2) in terms of the diameter of the hollow tube d.

calculate the length of the solenoid (l2)   in meters.

calculate the magnitude of the magnetic field at the center of the solenoid in teslas.

explanation:

the assestment will probley apele with cause and effect