Acar is rolling backward when it hits the gas. after 8.25 s it is moving forward at 8.62m/s, and is 12.9m to the right of its starting pount. what was its starting velocity ?

Explanation:

The given data is as follows.

        Final velocity (v) = 8.62 m/s,         Initial velocity () = ?

         time = 8.25 sec,          distance (s) = 12.9 m

Hence, formula to calculate the initial velocity is as follows.

                   v =

                 8.62 m/s =

                = 8.62 m/s - 8.25a ......... (1)

Also,   s = ...... (2)

Therefore, substitute the value of from equation (1) into equation (2) as follows.

                s =

               s = ....... (3)  

Now, putting the values of s and t into equation (3) as follows.

         s =  

        12.9 m =  

               a = 1.71  

Therefore, using equation (1) the value of initial velocity will be as follows.

                      =

                              =

                              = -5.49 m/s

Thus, we can conclude that starting velocity of the car is -5.49 m/s.

i had this question and the answer was 3.15 miles.

martina travels from school to her mom's office. from there, she walks to school. after school, she walks to the library and then to a friends house before finally ending back at home. find martina's total distance traveled.

a) 0 miles  

b) 0.4 miles  

c) 1 mile  

d) 3.15 miles