Atrain traveling at 18.2 m/s accelerates to 39.9 m/s over a distance of 1250 m. how long did it take the train to cover this distance?

43.4 s

Explanation:

First of all, we can find the acceleration of the train by using the equation:

where

v = 39.9 m/s is the final speed

u = 18.2 m/s is the initial speed

a is the acceleration

d = 1250 m is the distance covered

Solving for a,

And now we can fidn the time taken, by using the formula:

where is the circuit diagram ?

well clustered together.

points close on a scatter diagram