An air-track glider attached to a spring oscillates between the 15.0 cm mark and the 68.0 cm mark on the track. the glider completes 7.00 oscillations in 31.0 s . what is the period of the oscillations?

4.42 s

Explanation:

The frequency of the oscillation is given by the ratio between the number of complete oscillations and the time taken:

where for this glider, we have

N = 7.00

t = 31.0 s

Substituting, we find

Now we now that the period of oscillation is the reciprocal of the frequency:

So, substituting f = 0.226 Hz, we find:

answer: at 24 february, 2014 the population gets twice of its initial population.

explanation:

since we have given that

the population for alpha city, t years after january 1, 2004 is given as

first we find out the initial population, i.e. t=0,

so, our quadratic equation becomes,

according to question, we have said that if the population has twice its initial population, then it becomes

so, time taken to reach this above mentioned population is given by

now, we know that time can't be negative so, we take t=9.149 years.

hence, at 24 february, 2014 the population gets twice of its initial population.

find the surface area of the sphere to the nearest square unit. use a calculator.

a. 254 in.2

b. 64 in.2

c. 127 in.2

d. 1,018 in.2