The half-life of carbon -14 is 5730 years. what fraction of carbon-14 would remain after 11,460 years?

= 1/4

Explanation:

Using the formula;

N = O × (1/2)^t;

Where N is the new mass after decay, while O is the original mass of the radioactive isotope before decay, while t is the number of half lives.

Therefore;

Number of half lives = 11, 460/5730 = 2 half lives

Thus;

New fraction = 1 × (1/2)²

                      = 1/4

Therefore, the fraction that will remain after decay is 1/4 of carbon-14.

i think the answer would be b

the area between the graph and the t axis