Physics, 31.01.2020 00:04 shavonfriend27

One uniform sphere of matter has a radius of 0.50 m and a mass of 65 kg. a second uniform sphere has a radius of 0.80 m and a mass of 87 kg. the surfaces of the spheres are 1.20 m apart, as measured on a line drawn between the centers of the spheres. what is the magnitude of the gravitational force that each sphere exerts on the other?

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Answer from: drewje12

We have that for the Question, it can be said that the magnitude of the gravitational force that each sphere exerts on the other is

F=6.1*10^{-8}N

From the question we are told

One uniform sphere of matter has a radius of 0.50 m and a mass of 65 kg. A second uniform sphere has a radius of 0.80 m and a mass of 87 kg. The surfaces of the spheres are 1.20 m apart, as measured on a line drawn between the centers of the spheres. What is the magnitude of the gravitational force that each sphere exerts on the other?

Generally the equation for the Gravitational force is mathematically given as

$F =\frac{Gm1m2}{r^2}\\\\Therefore\\\\F =\frac{Gm1m2}{r^2}\\\\F=\frac{6.69x10^-11 (65)(87)}{2.5^2}\\\\$

F=6.1*10^{-8}N

Therefore

the magnitude of the gravitational force that each sphere exerts on the other is

F=6.1*10^{-8}N

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Answer from: lisilyn2437

$6.04\cdot 10^{-8}N$

Explanation:

The magnitude of the gravitational force between the two spheres is given by:

$F=G\frac{m_1 m_2}{r^2}$

where

G is the gravitational constant

m1 , m2 are the masses of the two spheres

r is the distance between the centres of the two spheres

Here we have:

m1 = 65 kg is the mass of the first sphere

m2 = 87 kg is the mass of the second sphere

the distance between the centres of the two spheres is equal to the sum of the radius of each sphere and the distance between the surfaces:

r = 0.50 m + 0.80 m + 1.20 m = 2.50 m

Substituting the numbers into the formula, we find:

$F=(6.67\cdot 10^{-11} )\frac{(65 kg)(87 kg)}{(2.50 m)^2}=6.04\cdot 10^{-8}N$

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