If two identical conducting spheres are in contact, any excess charge will be evenly distributed between the two. three identical metal spheres are labeled a, b, and c. initially, a has charge q, b has charge -q/2, and c is uncharged.

a. what is the final charge on each sphere if c is touched to b, removed, and then touched to a?
b. starting again from the initial conditions, what is the charge on each sphere if c is touched to a, removed, and then touched to b?

a. A: , B: , C:

When two conducting spheres touch, the charge on them is redistributed such that the potential on the two spheres is the same:

where Q refers to the charge and C to the capacitance of the sphere. For identical spheres, the capacitance is the same, so the previous equation becomes

which means that the charge distributes equally on the two spheres.

Here initially we have:

Sphere A: charge of q

Sphere B: charge of -q/2

Sphere C: charge of 0

At first, sphere C is touched to sphere B. Since the total charge of the two sphere was

After touching each sphere will have a charge half of this value:

Then sphere C (charge of -q/4) touches sphere A (charge of +q). So the total charge is

Since the charge distributes equally, each sphere will receive 1/2 of this charge:

So the final charge on the 3 spheres will be

A: , B: , C:

b. A: , B: , C:

At first, sphere C is touched to sphere A. Since the total charge of the two sphere was

After touching each sphere will have a charge half of this value:

Then sphere C (charge of q/2) touches sphere B (charge of -q/2). So the total charge is

Since the charge distributes equally, each sphere will receive 1/2 of this charge, which simply means a charge of zero:

So the final charge on the 3 spheres will be

A: , B: , C:

it takes about 30 days for it to break down