The moment of inertia of a uniform-density disk rotating about an axle through its center can be shown to be . this result is obtained by using integral calculus to add up the contributions of all the atoms in the disk. the factor of 1/2 reflects the fact that some of the atoms are near the center and some are far from the center; the factor of 1/2 is an average of the square distances. a uniform-density disk whose mass is 16 kg and radius is 0.19 m makes one complete rotation every 0.2 s. (a) what is the moment of inertia of this disk? entry field with correct answer 0.2888 kg · m2 (b) what is its rotational kinetic energy? entry field with correct answer 142.52 j (c) what is the magnitude of its rotational angular momentum? entry field with incorrect answer now contains modified data kg · m2/s