For a satellite to be in a circular orbit 590 km above the surface of the earth, what orbital speed must it be given? express your answer with the appropriate units.

7.57 km/s

Explanation:

The gravitational force on the satellite provides the centripetal force that keeps the satellite in circular orbit, so we can write:

where

G is the gravitational constant

is the Earth's mass

m is the satellite's mass

r = R+h is the distance of the satellite from the Earth's centre, where:

is the Earth's radius,

is the altitude of the satellite above Earth

v is the orbital speed of the satellite

Solving the equation for v, we find

the displacement produced by the body.  

the amount of force subjected to the body.  

the angle between the direction of force and displacement

air exerts forces on falling objects near earth’s surface.

explanation:

the term 'free falls' refer to object that are falling towards the earth, in a situation in which gravity is the only force acting on the object.

for an object in free fall, the acceleration is constant (g, the gravitational acceleration), and so the velocity of the object constantly increases.

for objects near earth's surface, there is always another force acting on the object: the resistance due to the air. this force is opposed to the direction of fall of the object, and it is proportional to the velocity of the object, so as the object falls down, this force increases up to a point when it balances the force of gravity, and the object continues its motion at constant velocity (called terminal velocity). since in this case gravity is not the only force acting on the object, we are not in a situation of free fall.