Itraveled 3.8 miles in 12 minutes. calculate my average velocity in miles per hour. 2) a sprinter increased his/her speed from 18 mph to 28 mph over 3.5 seconds. calculate his/her acceleration.

1) Average velocity: 19 mi/h

The average velocity is given by:

where

d is the displacement

t is the time taken

In this problem,

d = 3.8 mi is the displacement

is the time taken

Substituting,

Note that this is actually the average speed, not the average velocity, since there is no information about the direction of the motion.

2)

The acceleration is given by

where we have

v = 28 mph is the final velocity

u = 18 mph is the initial velocity

t = 3.5 s is the time taken

Conerting the time from seconds to hours,

So the acceleration is

unlike poles attract

when jerome paddle in flowing river towards east the net speed of jerome will increase

so the net speed of jerome will be given as

now the speed of paul will be same as it is given as he is running on the ground

so

so here we can say since the speed of jerome is more so he will win the race

now as we know the distance so the time difference is given as

so jerome will reach first and the time difference will be 203.55 s or 3.4 min