An object is placed a distance of twice the focal length away from a diverging lens. what is the magnification of the image?

1/3

Explanation:

We can solve the problem by using the lens equation:

where

f is the focal length

p is the distance of the object from the lens

q is the distance of the image from the lens

Here we have a divering lens, so the focal length must be taken as negative (-f). Moreover, we know that the object is placed at a distance of twice the focal length, so

So we can find q from the equation:

Now we can find the magnification of the image, given by:

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