Achild sits 6 m away from the center of the merry go round. the centripetal acceleration acting on the child’ is 3.6 m/s^2. what is the tangential velocity of the child?
a 4.65 m/s
b 21.6
c 0.6 m/s
d 1.67 m/s

The centripetal acceleration is related to the tangential velocity according to the equation below.  

a=v²/r where v is the tangential velocity and r the radius of the circular path.

thus v²=a×r

From the question provided, r=6m acceleration= 3.6m/s²

Therefore using these values in the formula v²=a×r

v=√(3.6×6)

v=√21.6

v=4.65

The answer is A. 4.65 m/s

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