Aproton and an electron in a hydrogen atom are separated on the average by about 5.3 × 10−11 m. what is the magnitude and direction of the electric field set up by the proton at the position of the electron? the coulomb constant is 8.99 × 109 n · m2 /c 2 . 1. 5.12068 × 1011 n/c away from the proton 2. 8.19309 × 10−8 n/c toward the proton 3. 27.1396 n/c away from the proton 4. 27.1396 n/c toward the proton 5. 5.12068 × 1011 n/c toward the proton 6. 8.19309 × 10−8 n/c away from the proton

1. 5.12068 × 1011 N/C away from the proton

Explanation:

The electric field produced by a single point charge is given by:

where

k is the Coulomb's constant

q is the magnitude of the charge

r is the distance from the charge

In this problem, we have:

is the charge of the proton

is the distance at which we want to calculate the field

is the Coulomb's constant

Substituting into the formula,

And the direction of the electric field produced by a positive charge is away from the charge, so the correct answer is

1. 5.12068 × 1011 N/C away from the proton

okay i have so many questions. but the big one here is: um wt..f is this mess? ?

answer: b.

explanation: