Aswitch that connects a battery to a 10 µf capacitor is closed. several seconds later you find that the capacitor plates are charged to 30 µc. what is the emf of the battery?

3 V

Explanation:

The relationship between capacity (C), charge stored (Q) and potential difference across a capacitor (V) is

(1)

The problem asks us to find the emf of the battery several seconds after the switch has been closed: this means that the capacitor had enough time to fully charge, so the potential difference across the capacitor (V) is equal to the emf of the battery.

Since we have:

We can solve the equation for V, and we find

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explanation: