You exert a 100-n pull on the end of a spring. when you increase the force by 20% to 120 n, the spring's length increases 9.0 cm beyond its original stretched position. part a: what is the spring constant of the spring? (i got k = 222 n/m)

part b: what is its original displacement? (i can't really figure this part out)

A) 222 N/m

Explanation:

Hook's law gives us the relationship between force (F), displacement with respect to the original length (x) and spring's constant (k):

In this part of the problem, we have:

F = 120 N - 100 N = 20 N is the new force applied

x = 9.0 cm = 0.09 m is the displacement relative to the initial stretched position

Solving the equation for k, we find the spring constant

B) 45 cm

We can use Hook's law also for this part of the exercise:

where this time we have

F = 100 N (the original pull applied)

k = 222 N/m

Solving the equation for x, we find the original displacement:

the expression 15n + 2(3p) represents the amount isaiah spent buying gasoline and snacks, where n represents the price of each gallon of gasoline and p represents the cost of each snack that he bought. which statement is true about the amount isaiah spent?