A2 kg rock is dropped from the top of a 30 m high building calculate the ball at the time that it strikes the ground

48.54kgm/s

Explanation:

Momentum is defined as the product of mass and velocity of an object. Mathematically,

Momentum = Mass×velocity

Given mass = 2kg

Velocity of the body as it strikes the ground can be gotten using the equation of motion v² = u²+2as where;

v = final velocity of the body

u = initial velocity of the body = 0m/s

a = g = acceleration due to gravity

S = h = height covered by the rock

The equation will then become

v²= u²+2gh

v² = 0²+2(9.82)(30)

v² = 589.2

v = √589.2

v = 24.27m/s

the momentum of the ball at the time that it strikes the ground = mass × velocity

= 2×24.27

= 48.54kgm/s

answer: he got 23

explanation: