Several light bulbs, each of resistance 1.5 ω, are connected in a series across a 120 v source of emf. if the current through the circuit is 2 a, how many light bulbs are there in the circuit?

40 light bulbs

The total resistance of components or bulbs in series is given as the sum of resistance of all the components.

Thus; if there are bulbs in series each with a resistance of 1.5 Ω, the the total resistance will be; 1.5nΩ

From the ohms law;

V = IR , where V is the voltage, I is the current and R is the resistor.

Thus; R = V/i

         R = 120/2

            = 60 Ω

But, there are n bulbs each with 1.5 Ω; thus there are;

n = 60/1.5

 = 40 Bulbs

the answer would be 32*f