Arectangular coil that has a length of 18.0 cm and a width of 6.5 cm containing 11 loops lies flat on your desk as shown on this page. a uniform magnetic field of magnitude 5.20 × 10 − 5 t points towards the right of this page. if a 6.50-a counterclockwise current flows through the coil, (a) determine the torque on the coil.\

Explanation:

The torque exerted on a current-carrying coil by a magnetic field perpendicular to the area of the coil is given by:

where:

N = 11 is the number of loops

is the area of the coil

I = 6.50 A is the current

is the magnitude of the magnetic field

Substituting into the equation, we find the torque:

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