Bill forgets to put his car in park and it starts rolling west. when it is moving at a speed of 3.5 m/s, it collides with tanya's car, which is moving at a speed of 2m/s east. bill's car bounces backward (to the east) at a speed of 2 m/s. bill's car has a mass of 900 kg, and tanya's car has a mass of 1100 kg.

a. what is the total momentum of the system before collision?

b. what is the total momentum of the system after the collision?

c, what is the velocity of tanya's car after the collision?

PART A)

momentum of Bill's car

mass = 900 kg

speed = 3.5 m/s towards west

so momentum of this car given as

Similarly momentum of Tanya's car

mass = 1100 kg

speed = 2 m/s towards East

so momentum will be

Total momentum of both cars will be

Towards west

PART B)

Since there is no external force on the system of two cars

So here total momentum of both cars will remains conserved

So final momentum of two cars will be same as initial momentum

towards west

Part C)

final momentum of Bills car

Towards East

now we have

towards west

when two balls of the different masses are dropped from equal height, they reach the ground at the same time .this is because they experience the same acceleration.

the acceleration is independent of mass.

thus when they are dropped they will always maintain the same velocity and travel the same distance (neglect air resistance of course) at the same time.