Ajet engine develops 1.0 x 10 n of thrust to move an airplane forward
at a speed of 9.0 x 10 km/h. what
is the power output of the engine?

Power,

Explanation:

Given that :

Force applied to the engine,

Speed of the engine,

To find :

The power output of the engine

Solve :

Power output of the engine is given by :

W is the work done

t is the time taken

Also, and

So, the power output of the engine is .

it becomes positively charged by charging it

the minimum constant speed at which she can catch the train is 2.7 m/s

given:

acceleration = 0.6

time = 4.5 s

to find:

velocity = ?

formula used:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

solution:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

v = 0 + (0.6 × 4.5)

v = 2.7 m/s

the minimum constant speed at which she can catch the train is 2.7 m/s