Car a start 10 meters ahead of car b. car a moves at v= (3.0i+0j) m/s and car b moves forward at v=(7.0i+0j)m/s how many seconds does it takes car b to catch up

Do both cars leave the starting line at the same time ?  That's kind of important.  I'll assume that they both start out at the same time, and now I'll proceed to answer the question that I have invented.

-- Car B moves 4 m/s faster than Car A .  

-- So Car-A's lead shrinks by 4 meters every second after they start.

-- It takes (10/4) = 2.5 seconds for Car-A's lead to shrink to zero.

-- So Car-B overtakes Car-A 2.5 seconds after they start.

initial speed when it is dropped is 150 ft/s

now at the same moment the acceleration due to gravity is perpendicular to its velocity

so as we know that

now we have centripetal acceleration a = 32 ft/s^2 as its perpendicular to velocity

while tangential acceleration at the same moment will be zero

so

now radius of curvature is given as

so the radius of curvature just after it is dropped is 703.125 ft