An astronomer at the equator measures the doppler shift of sunlight at sunset. from this, she calculates that earth's tangential velocity at the equator is 465 m/s. the centripetal acceleration at the equator is 3.41 * 10^-2 m/s2. use this data to calculate earth's radius.

Answer : Radius of Earth is 6,340 Km.

Explanation

It is given that,

Tangential velocity of Earth at the equator, v = 465 m/s

Centripetal acceleration at the equation is,

We know that the relation between centripetal acceleration and tangential velocity is :

..........(1)

Where,

v is tangential velocity

r is the radius

Putting all values in equation (1)

or

The Earth's radius is 6,340 Km. Hence, this is the required solution.

here we know that ball will drop down by total distance 3.2 m

so here we know that

now using kinematics

now in the same time it will cover horizontal distance of 0.75 m

so speed of the ball will be

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