What is the final velocity of a car that is originally traveling 12 m/s and then undergoes an acceleration of 2.3m/s squared for a distance of 130m?

To solve this problem we use the general kinetic equations.

We need to know the time it takes for the car to reach 130 meters.

In this way we have to:

Where

= initial position

= initial velocity

= acceleration

= time

= position as a function of time

.

We use the quadratic formula to solve the equation.

t = 6.63 s and t = -17.1 s

We take the positive solution. This means that the car takes 6.63 s to reach 130 meters.

Then we use the following equation to find the final velocity:

Where:

= final speed

The final speed of the car is 27.25 m/s

answer; (arch); good luck

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