Consider a charged parallel-plate capacitor. how can its capacitance be halved?

- doubling k, the permittivity of the dielectric

- doubling A, the area of each plate

- halving d, the distance between the two plates

Explanation:

The capacitance of a charged parallel-plate capacitor is given by:

where

k is the relative permittivity of the dielectric inside the capacitor

is the vacuum permittivity

A is the area of each plate of the capacitor

d is the distance between the two plates

From the formula, we see that we can halve the capacitance by doing any of the following:

- doubling k, the permittivity of the dielectric

- doubling A, the area of each plate

- halving d, the distance between the two plates

what experimental evidence led scientists to change from the previous model to this one?

a few of the positive particles aimed at a gold foil seemed to bounce back.

the colors of light emitted from heated atoms had very specific energies.

experiments with water vapor showed that elements combine in specific proportions.

cathode rays were bent in the same way whenever a magnet was brought near them.