Two charges of -5×10^-9 c and -1.5×10^-9 c are separated by a distance of 43cm. find the equilibrium position for a third charge of +1.1×10^-8 c by identifying its distance from the first charge q1.

Solution

In this question we have given

Charge,

Charge,

Charge,

Distance between Charge and ,d=43cm=.43m

Let the distance between charge and , is x

Therefore,distance between charge and , will be=(.43-x)

We know By Couloms law, Force on Charge due to charge which are seperated by distance d is given by following equation

............(1)

Here, K=

Therefore,

Force on Charge due to charge

..(2)

Similarly,

Force on Charge due to charge

..(2)

In equilibrium condition,

on solving we get

x=.277m

0r x=28cm

The distance between charge and , is 28cm

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