The volume of a gas–filled balloon is 30.0 liters at 313 k and 153 kilopascals pressure. what would the volume be at standard temperature and pressure (0°c and 100 kilopascals)?

Use the combined and idea gas law to solve this:

Let the subscript ₁ represent the initial values from pressure volume and temperature and ₂ for final.

So we know

P₁ = 153kpa

V₁ = 30L

T₁ = 313K

P₂ = 100kpa

T₂ = 0 Celsius which is 273 K

So we need to solve for volume:

= P₂V₂

Then we divide by Pressure on the right to give:

/ P₂ = V₂

Plugging all that in:

/ 100kpa = V₂

V₂ = 40.03 L

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