In which scenario is the least amount of work done on a crate? a force of 120 n moves it 25 m. a force of 115 n moves it 26 m. a force of 130 n moves it 22 m. a force of 125 n moves it 27 m.

A force of 130 N moves it 22 m = least work done

Explanation:

Work done by an object is given by the product of force and the distance covered by it. Mathematically, it can be written as :

W = F  × d

In first case, F = 120 N and d = 25 m

Work done, W = 3000 Joules

In second case, F = 115 N and d = 26 m

Work done, W = 2990 Joules    

In third case, F = 130 N and d = 22 m

Work done, W = 2860 Joules  

In fourth case, F = 125 N and d = 27 m

Work done, W = 3375 Joules

So, it is clear that the least amount of work is done on a crate is when a force of 130 N is acting and distance covered is 22 m.