** urgent** the voltage across the primary winding is 350,000 v, and the voltage across the secondary winding is 17,500 v. if the secondary winding has 600 coils, how many coils are in the primary winding? a- 30 coilsb- 583 coilsc- 12,000 coilsd- 332,500 coils

As we know that in transformers we have

here we know that

now from above equation we will have

12000 coils

Explanation:

It is given that,

The voltage across the primary winding V₁ = 350,000 V

The voltage across the secondary winding V₂ = 17500 V

Number of coils in secondary winding, N₂ = 600

We have to find the number of coils in primary winding. It can be calculated suing turn ratio equation as :

Hence, the number of coils in primary winding is 12,000

12,000 coils. The primary winding has 12,000 coils.

In order to solve this problem we have to use the relation for a transformer Vp/Vs = Np/Ns, where Vp is the voltage across the primary winding, Vs in the voltage across the secondary winding, Np is the numbers of coils in the primary winding, and Ns is the number of coils en the secondary winding.

With Vp = 350,000 V, Vs = 17,500 V, and Ns = 600 coils:

350,000 V/17,500 = Np / 600 coils

Np = (600 coils x 350,000 V) / 17,500 V

Np = 210,000,000/ 17,500 coils

Np = 12,000 coils

12,000 coils

Explanation:

edge