One charge is decreased to one-third of its original value, and a second charge is decreased to one-half of its original value. how will the electrical force between the charges compare with the original force? a- it will increase to six times the original force. b- it will increase to thirty-six times the original force. c- it will decrease to one-sixth the original force. d- it will decrease to one-thirty-sixth the original force.

The electric force will decrease to one-sixth the original force, therefore the correct option is (C).

The electric force between two charge particle is given by the Coulomb's law.

here, q1q2 are the charges and r is the distance between particles.

The electric force when the first charge is decreased to one-third and second charge is decreased to one half.

F1=\frac{q1q2}{2*3*r^2}[/tex]

on dividing

F1=

Therefore electric force will decrease by 1/6 of the current value.

it may be wrong but i think its a

we need answer choices