In order to calculate the weight of an object sitting on the earth's surface, one would use the following formula: f = gme m where g = 6.674 í— 10-11 m3 is the universal gravitational constant, g r2 kgs2 me = 5.97 í— 1024 kg is the mass of the earth (also a constant), r is the radius of the earth at the object's location (measured in m), and m = the mass of the object (measured in kg). calculate the weight of a penny (to the correct number of significant figures) using this formula if you measure the penny's mass to be 2.5 g and the radius of the earth at the penny's location to be 6.383 í— 103 km. use unit algebra to express the unit for weight as some combination of the metric system's standard units for mass, length, and time.

Iwould say earthquakes.

The figure is missing but we can answer anyway.the correct answer is "releasing the string". in fact, when the person is holding the bow and the arrow, the kinetic energy of the arrow is still zero (because the arrow is not moving). the moment the arrow is released, it acquires a velocity v, so its kinetic energy will become different from zero: where m is the mass of the arrow and v its velocity.  all the other options, instead, do not increase the kinetic energy of the system: -  pulling farther back on the string : this will just increase the elastic potential energy of the system-  holding the arrow higher: this will increase the gravitational potential energy of the system (which is given by u=mgh, where h is the height above the ground)-  decreasing the mass of the arrow: this will decrease the gravitational potential energy of the system (which is given by u=mgh, where m is the mass)

Your answer would be the sun