A(n) 83 kg fisherman jumps from a dock into a 139 kg rowboat at rest on the west side of the dock. if the velocity of the fisherman is 3.1 m/s to the west as he leaves the dock, what is the final velocity of the fisherman and the boat? answer in units of m/s.

here we can say that there is no external force on fisherman and dock

so here we will use momentum conservation theory

As per momentum conservation

initial momentum of fisherman + boat = final momentum of fisherman + boat

now we will have

so the speed of boat and fisherman will be 1.16 m/s

what is the question because that is not a question.

air exerts forces on falling objects near earth’s surface.

explanation:

the term 'free falls' refer to object that are falling towards the earth, in a situation in which gravity is the only force acting on the object.

for an object in free fall, the acceleration is constant (g, the gravitational acceleration), and so the velocity of the object constantly increases.

for objects near earth's surface, there is always another force acting on the object: the resistance due to the air. this force is opposed to the direction of fall of the object, and it is proportional to the velocity of the object, so as the object falls down, this force increases up to a point when it balances the force of gravity, and the object continues its motion at constant velocity (called terminal velocity). since in this case gravity is not the only force acting on the object, we are not in a situation of free fall.