Awaiter is carrying a tray above his head and walking at a constant velocity. if he applies a force of 5.0 newtons on the tray and covers a distance of 10.0 meters, how much is the work being done? a. 0 joules b. 2 joules c. -2 joules d. 50 joules e. -50 joules

(A) 0 Joules

Explanation:

The force applied exists in the vertical direction only. There is no displacement in the vertical direction. (Work)=(Force in y direction) x (Displacement in y direction) = (Force) x 0 = 0 J

the tires are rotating at 0.434 rpmlinear speed=45 m/sdiameter=0.550 mradius=0.275 mnow v= rωω= v/rω=45/0.275ω=163.6 rad/sω=163.6 rad/s (1rev/2π rad) (60s/1m)ω=1563 rpm