Ej is taking his little sister, ebony, on her first carousel ride. his mass is 75.0 kg, and her mass is 10.0 kg. they ride the same horse, and it is 11.0 meters from the center of the carousel. if their angular momentum is 14020 kg m2/s, what is their linear speed?

In this question we have given

mass of Ebony=75Kg

His sister mass=10kg

here total mass=mass of Ebony+his sister mass

m=75+10  

m=85kg

radius of circular path=11m

angular momentum=14020kgm^2/s

we know that,

angular momentum=interia*angular speed

angular momentum=I*w(1)

here, interia  I=mr^2  

and w=v/r (here v is the linear velocity and r is radius)

put  values of I and w in equation (1)

angular momentum=mr^2*v/r

angular momentum = mvr  

14020 = (75+10) x v x 11  

v = 14020/(85x11) = 14.99m/s

the answer is b

explanation: