What is the internal energy of 3.00 mol of n2 gas at 25 degrees c? to solve this problem, use the equation: u electronic gas = 5/2nrt. remember that r = 8.31 j/(mol-k) and k = degrees + 273. a. 37, 100 j b. 18,600 j c. 1560 j d. 623 j

Given data

Determine Internal energy of gas N₂,  (U) = ?

Temperature (T) = 25° C

                          = 25+273 = 298 K,

Gas constant (R) = 8.31 J/ mol-K ,

Number of moles (n) = 3 moles,

Internal energy of N₂

Internal energy is a property of thermodynamics, the concept of internal energy can be understand by ideal gas. For example N₂, the observations for oxygen and nitrogen at atmospheric temperatures,  f=5,  (where f is translational  degrees of freedom).

       So per kilogram of gas,

          The internal energy (U) = 5/2 .n.R.T

                                                  = (5/2) × 3 × 8.31 ×298

                                                  = 18572.85 J

The internal energy of the N₂ is 18,572.85 J and it is approximately equal to 18,600 J given in the option B.

would be false hope this out

c. magnitude and direction