Devon places sliced potatoes in a package of aluminum foil. he puts a metal grate over a campfire and sets the package on the grate. he warms his hands over the fire while he waits and watches the hot air carry ashes into the sky. when he removes the foil package, the grate and foil are hot, and the food is cooked. which part of this scenario represents conduction? the food cooks inside the foil. devon warms his hands over the fire. the hot air rises into the sky. the grate is hot when devon is done cooking.

 The correct answer is "The food cooks inside the foil".

Explanation:

In conduction , there is no actual movement of matter. Heat flows from the hotter body to the colder body but when the two bodies are placed in contact with each other.

In convection, there is a physical movement of matter.

Radiation is the emission of the energy. Heat travels through a vacuum in the radiation.

In the given problem, Devon places sliced potatoes in a package of aluminum foil. He puts a metal grate over a campfire and sets the package on the grate.  

When he removes the foil package, the grate and foil are hot, and the food is cooked. Here, the heat is transferred from the campfire to the metal grate to the aluminium fire and then to the food. The metal grate and the aluminium foil are in contact with each other. Here, the conduction takes place.

Therefore, the scenario, "The food cooks inside the foil" represents the conduction from the given option.

the food makes contact with the foil wich represents conduction so the answer is  A, hope this helps ( ;w;)

Explanation:

uranium fissions/breaks up giving out energy and neutrons

the minimum constant speed at which she can catch the train is 2.7 m/s

given:

acceleration = 0.6

time = 4.5 s

to find:

velocity = ?

formula used:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

solution:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

v = 0 + (0.6 × 4.5)

v = 2.7 m/s

the minimum constant speed at which she can catch the train is 2.7 m/s